0=1.9t^2+56t+30

Solution for 0=1.9t^2+56t+30 equation:

0=1.9t^2+56t+30

We move all terms to the left:

0-(1.9t^2+56t+30)=0

We add all the numbers together, and all the variables

-(1.9t^2+56t+30)=0

We get rid of parentheses

-1.9t^2-56t-30=0

a = -1.9; b = -56; c = -30;
Δ = b2-4ac
Δ = -562-4·(-1.9)·(-30)
Δ = 2908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2908}=\sqrt{4*727}=\sqrt{4}*\sqrt{727}=2\sqrt{727}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-2\sqrt{727}}{2*-1.9}=\frac{56-2\sqrt{727}}{-3.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+2\sqrt{727}}{2*-1.9}=\frac{56+2\sqrt{727}}{-3.8}
$